5x^4+4x^2-12=0

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Solution for 5x^4+4x^2-12=0 equation:


Simplifying
5x4 + 4x2 + -12 = 0

Reorder the terms:
-12 + 4x2 + 5x4 = 0

Solving
-12 + 4x2 + 5x4 = 0

Solving for variable 'x'.

Factor a trinomial.
(-2 + -1x2)(6 + -5x2) = 0

Subproblem 1

Set the factor '(-2 + -1x2)' equal to zero and attempt to solve: Simplifying -2 + -1x2 = 0 Solving -2 + -1x2 = 0 Move all terms containing x to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1x2 = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1x2 = 0 + 2 -1x2 = 0 + 2 Combine like terms: 0 + 2 = 2 -1x2 = 2 Divide each side by '-1'. x2 = -2 Simplifying x2 = -2 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(6 + -5x2)' equal to zero and attempt to solve: Simplifying 6 + -5x2 = 0 Solving 6 + -5x2 = 0 Move all terms containing x to the left, all other terms to the right. Add '-6' to each side of the equation. 6 + -6 + -5x2 = 0 + -6 Combine like terms: 6 + -6 = 0 0 + -5x2 = 0 + -6 -5x2 = 0 + -6 Combine like terms: 0 + -6 = -6 -5x2 = -6 Divide each side by '-5'. x2 = 1.2 Simplifying x2 = 1.2 Take the square root of each side: x = {-1.095445115, 1.095445115}

Solution

x = {-1.095445115, 1.095445115}

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